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The next example illustrates the algebraic technique of “multiplying by the conjugate,” which can be used to treat some indeterminate forms involving square roots.
Evaluate .
Solution We check that has the indeterminate form 0/0 at x = 4:
Note, in Step 1, that the conjugate ofis, so.
Step 1. Multiply by the conjugate and cancel.
Step 2. Substitute (evaluate using continuity).
Because is continuous at x = 4,
Evaluate .
Solution We note that yields 0/0 at h = 5:
The conjugate of is , and
The denominator is equal to
Thus, for h ≠ 5,
We obtain
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As preparation for the derivative in Chapter 3, we evaluate a limit involving a symbolic constant.
Calculate , where a is a constant.
Solution We have the indeterminate form 0/0 at h = 0 because
Expand the numerator and simplify (for h ≠ 0):
The function h + 2a is continuous (for any constant a), so
Solution By definition, is a positive solution to the equation x^2=2. We set f(x) = x^2-2 and observe that f(1) =-1<0 and f(2)=2>0. Therefore, by Corollary 2, there exists a real number c in (1,2) such that c^2=2. Hence exists and is a real number.